Real Numbers,
NCERT Solutions for Class 10 Maths Chapter 1
Important NCERT Questions
Real Numbers
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 1.1
Page No:7
Questions No:1 Part:3
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867 and 255
Since 867 > 255, we apply the division lemma to 867 and 255 to obtain
867 = 255 × 3 + 102
Since remainder 102 ≠ 0, we apply the division lemma to 255 and 102 to obtain
255 = 102 × 2 + 51
We consider the new divisor 102 and new remainder 51, and apply the division lemma to obtain
102 = 51 × 2 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 51, Therefore, HCF of 867 and 255 is 51.
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