A Bus of mass 500 kg is moving with a velocity of 5 metre per second and is acted upon by a forward force of 500 Newton due to engine and retarding force of 200 Newton due to friction. Velocity of bus after 20 seconds will be:
Given, m = 500 kg, u = 5 m/s and t = 20 s.
Resultant force, F = 500 – 200 = 300 N
Acceleration, a = F/m
= 300/500
= 0.6 m/s²
by question of motion:
v = u + at
= 5 + 0.6 x 20
= 17 m/s
Share
(B) 17 m/s