Check whether (5, – 2), (6, 4) and (7, – 2) are the vertices of an isosceles triangle.

Given points: A(5, -2), B(6,4) and C(7,-2) are vertices of triangle.
Using distance formula: √((x₂-x₁)²+(y₂-y₁)²)
AB = √((6-5)²+[4-(-2)]²)P = √(1+36) = √37
BC = √((7-6)²+(-2-4)²) = √(1+36) = √37
CA = √((5-7)²+[-2-(-2)]²) = √(4+0) = 2
Here, AB = BC ≠ AC
Hence, the points (5,-2),. (6,4) and (7,-2) are the vertices of an isosceles triangle.

Here is the video explanation 😃👇