We apply the identity with a = x and b = 1/2y. The middle term simplifies because the number two in the formula cancels out with the denominator two of the fraction.
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Ayushree
Asked: In: Class 9 Maths
We substitute a = 3/4 s and b = 8t into the square identity. Squaring the terms independently and simplifying the middle multiplication step gives the final plain algebraic text solution.
Ayushree
Asked: In: Class 9 Maths
We apply the identity using the decimal values where a = 2.5p and b = 1.5q. Evaluating the squares of the decimals and their double product gives the final expanded form.
Ayushree
Asked: In: Class 9 Maths
We use the identity with a = 7/5 x and b = 3/2 y. Squaring the fractional coefficients and multiplying two with both terms yields the expanded expression with simplified fraction terms.
Ayushree
Asked: In: Class 9 Maths
We apply the identity by substituting a = 7x and b = 4y. Squaring both individual terms and calculating twice their product gives us the terms 49x square, 56xy, and 16y square.