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In Fig. 6.39, sides QP and RQ of ∆ PQR are produced to points S and T respectively. If ∠ SPR = 135° and ∠ PQT = 110°, find ∠ PRQ.

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NCERT math chapter 6 exercise 6.3 covers important theorems and facts regarding parallel lines, transversal lines, alternate angles, corresponding angles, interior angles, and exterior angles.

NCERT CLASS 9 Chapter 6 Exercise 6.3 Question No. 1
Page No. 107.
I need Video Solution for this Exercise 6.3.

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1 Answer

  1. ∠PQT + ∠PQR = 180°
    ⇒ 110° + ∠PQR = 180°
    ⇒ ∠PQT = 180° – 110° = 70°
    ∠SPR + ∠QPR = 180°
    ⇒ 135° + ∠QPR = 180°
    ⇒ ∠QPR = 180° – 135° = 45°
    In △PQR,
    ∠QPR + ∠PQR + ∠R = 180°
    ⇒ 70° + 45° + ∠R = 180°
    ⇒ 115° + ∠R = 180°
    ⇒ ∠R = 180° – 115° = 65°

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