NCERT Solutions for Class 8 Mathematics Chapter 16

Important NCERT Questions

Playing with Numbers Chapter 8 Exercise 16.2

NCERT Books for Session 2020-2021

CBSE Board

Questions No: 4

# If 31z5 is a multiple of 3, where z is a digit, what might be the values of z?

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Since 31z5 is a multiple of 3.

Therefore according to the divisibility rule of 3, the sum of all the digits should be a

multiple of 3.

Since z is a digit.

∴ 3+1+ z +5 = 9+ z ⇒ 9+z=9 ⇒ z=0

if 3+1+ z +5 = 9+ z ⇒ 9 + z = 12 ⇒ z=3

if 3+1+ z +5 = 9+ z ⇒ 9 + z = 15 ⇒ z=6

if 3+1+ z +5 = 9+ z ⇒ 9 + z = 18 ⇒ z=9

Hence, 0, 3, 6 and 9 are four possible answers.

Class 8 Maths Chapter 11 Exercise 16.2 Solution in Video

for more answers vist to:

https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-16/